Can you solve this problem?

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QansaGabeyle
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Can you solve this problem?

Post by QansaGabeyle »

Of course without going to the internet to get the answer. I have seen this before but the other day I tried to solve it and it made my head spin. Too many variables. Anyway in the end I managed to solve it but it took me a lot longer than I had anticipated.
Julia is as old as John will be when Julia is twice as old as John was when Julia's age was half the sum of their present ages. John is as old as Julia was when John was half the age he will be 10 years from now. How old are John and Julia?
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QansaGabeyle
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Re: Can you solve this problem?

Post by QansaGabeyle »

Damn no one even gave it a shot. Where are those of you who claim to be math wizs?
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Re: Can you solve this problem?

Post by zulaika »

dude...its Friday....why u gotta ruin it with this. :D
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Re: Can you solve this problem?

Post by Faisah »

They are the same age... :roll:
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Re: Can you solve this problem?

Post by Foxy22 »

The Solution: John is 30 years old and Julia is 40 years old.

An explanation:
Let Julia's age be a and let John's age be b.
The first sentence tells us that "Julia is as old as John will be when Julia is twice as old as John was when Julia's age was half the sum of their present ages".
"Half the sum of their present ages" is:
0.5*(a+b)
So "Julia's age was half the sum of their present ages", the following number of years ago:
a - (0.5*(a+b)) = 0.5*a-0.5*b
At that moment, "John's age" was:
b - (0.5*a-0.5*b) = 1.5*b-0.5*a.
So "twice that age" is:
3*b-a
"Julia's age will be twice that age", in the following number of years:
(3*b-a) - a = 3*b-2*a
At that moment, John will be:
b + (3*b-2*a) = 4*b-2*a
And we are told that "that's Julia's age", so:
a = 4*b-2*a
or
3*a = 4*b.

The second sentence tells us that "John is as old as Julia was when John was half the age he will be 10 years from now".
"10 years from now", John will be:
b+10
"Half that age" is:
0.5*b+5
"John was that age", the following number of years ago:
b - (0.5*b+5) = 0.5*b-5
At that time, "Julia was", the following number of years old:
a - (0.5*b-5) = a-0.5*b+5
And that "is John's current age", so:
b = a-0.5*b+5
or
a = 1.5*b-5.

Now we have two equations:
3*a = 4*b and a = 1.5*b-5.
Substitute a in the first equation for the value of a from the second equation and we get:
3*(1.5*b-5) = 4*b
Solving this equation, we get:
b=30
Since a = 1.5*b-5 :
a=40
So Julia's age is 40, and John's age is 30.


It's Friday... get a life!
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QansaGabeyle
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Re: Can you solve this problem?

Post by QansaGabeyle »

lol@Foxy22.......Nicely done.
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Re: Can you solve this problem?

Post by ms.nalia »

you actually spent time on that???

wow! :roll: :up:
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Re: Can you solve this problem?

Post by suga_n_spice »

qansa how r ur allergies comin along dear??
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Re: Can you solve this problem?

Post by QansaGabeyle »

I am much better. Thank you for asking suga.....How is school.
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Re: Can you solve this problem?

Post by Aerosmith »

QansaGabeyle good one bro.

Sadly I couldn't do it.
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