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Octavius


Thank you. I did some quick checking on the concept of transport error.They said this error is a computing error that occurs when someone switches the position of two adjacent digits in calculations. So, they divide the results by 9 to locate which numbers were switched.

Looks like we have math heads in here.


Integrate that show all your work. No cheating.

^

1) image error: it isn't visible
2) will you pay us to do your homework for you?

eliteSomali wrote:Looks like we have math heads in here.


Integrate that show all your work. No cheating.

LOL, you need help with your homework I see. What a cheat

LoL. That is not my homework. I want you guys to integrate it. Matter fact. Let me integrate it and post the solution only and you guys should tell me how I got the work? Sound like a deal?

Hey bro, this is the result from a quick entry into the walframalpha website, hope this helps if it was your homework

lol. Look at the integral you have and the one I posted. They aren't similar.

Here is the answer.

the answer is: Arctan([x+3)/root(6)]/root(6)

Lol I shall play this with the kids! Thanks macaanow

lol worked out what was going on in that trick, (does it make sense?)......A 2 digit number can be expressed as 10*d1 + d0

where d0 and d1 are the digit values, which are from 0 to 9

The digits' sum is (d0 + d1), and subtracting from the original number gives 9*d1

9*d1 = 10*d1 - d1 = 10*(d1-1) + (10-d1) giving digits (d1-1) and (10-d1) that add up to 9.

Thus getting 9

The formula 3n(n-1) + 1 is pretty interesting. You get the sequence; 1, 7, 19, 37, 61... (basically each element in the sequence is a progressively larger multiple of 6 bigger than the one before it. So 7 is 6 more than 1, 19 is 12 more than 7, and 37 is 18 more than 19 etc). You can make increasingly larger hexagonal shapes using the formula, with coins or dots or something like that. You start with one dot/coin, then you add 6 (7-1) dots around it to get a hexagon. You can add 12 dots around it (19-7) to get an even bigger one, and so on. You get something that looks like this: If you notice, the number of dots on each side increases by one each time, and the total number of dots on the outline of the hexagons is given by the formula n(2n-1).



Not really a math fact per se, but pretty cool.

Mother farax,i gave up gcse maths markay tessellation iyo tracing paper howshu gaadhay. Gcse d,kneegrow.

Baasto more like markuu macalin told you next week we are starting on pi.. Naxdiintii baad ka sow noqon weydey

Aisha i was good at maths. Till the day,anigoo hoody jumper iska xidhan oo coke la soo baxay,the Asian teacher threw my coke down the sink.gardaro.com. I stormed out hadi kale classkan jajabin laha.she offered to pay for it the next day.i said naaah. Anyway,let us not hijack the nerds thread.

Baasto you're funny. Seems we were both in the years where tesselation and tracing papers were used in Maths
I mostly hated loci problems, and bearings (all the stupid ship A and ship B business).