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ok I got stuck with this equation, well I need to isolate r so it can stand alone,
any of you geeks can help me on how to solve this shit?

the dots between pi and r are times sign's,

This is somewhat easy, but you could make a lot of mistakes.

I got

r = sqaure root (m/p*pi)

IRONm@N wrote:This is somewhat easy, but you could make a lot of mistakes.

I got

r = sqaure root (m/p*pi)

I see brother, well I will see if I get the same ,

abdisamad3 wrote:

IRONm@N wrote:This is somewhat easy, but you could make a lot of mistakes.

I got

r = sqaure root (m/p*pi)

I see brother, well I will see if I get the same ,

oh sorry, I meant

r = cube root (m/p*pi)

not sqaure root.

IRONm@N wrote:

abdisamad3 wrote:

IRONm@N wrote:This is somewhat easy, but you could make a lot of mistakes.

I got

r = sqaure root (m/p*pi)

I see brother, well I will see if I get the same ,

oh sorry, I meant

r = cube root (m/p*pi)

not sqaure root

that is what i got as well thanks for your time bro,

If that doesn't work try this answer

r = cube root (2m/3p*pi)

iron I got this final result
r=cube root m/6*pi*p

In my agricultural engineering course we use the same kind of equations but we plug in real data for the variables, for example our r, p, and m would all relate to a measurement of some kind with an exact number. That's the only kind of algebra I can do, when the variables and numbers actually mean something. If you give me a bunch of letters that mean shit I'll walk away, I hate algebra/trig/calculus unless its applied to a situation.

no its
r = cube root (2m/3p*pi)

in the brackets you get
m = (3*pi*r^2/4)*2pr
then after simplifying the 2 with the 4 it becomes

m = 3*pi*pr^3/2

2m = 3pi*r^3

r^3 = 2m/3pi*p

r = cube root (2m/3p*pi)

forget about the old one, this is should be right.

Monk-of-Mogadishu wrote:In my agricultural engineering course we use the same kind of equations but we plug in real data for the variables, for example our r, p, and m would all relate to a measurement of some kind with an exact number. That's the only kind of algebra I can do, when the variables and numbers actually mean something. If you give me a bunch of letters that mean shit I'll walk away, I hate algebra/trig/calculus unless its applied to a situation.

we do that as well sxb but this is just a math lesson we have go through, Iam not big fan of algebra my self,

IRONm@N wrote:no its
r = cube root (2m/3p*pi)

in the brackets you get
m = (3*pi*r^2/4)*2pr
then after simplifying the 2 with the 4 it becomes

m = 3*pi*pr^3/2

2m = 3pi*r^3

r^3 = 2m/3pi*p

r = cube root (2m/3p*pi)

forget about the old one, this is should be right.

well you might be right sxb,,I gotta re-calculate and see what I did wrong,

The answer is wrong.

Addoow wrote:The answer is wrong.

so you got a solution?

lol I did a re-calculation this time I get a whole new different result
r=cube root 6*pi*p/4*m